Solid of Revolution Calculator - Volume & Surface Area Online

Quick Examples — click to load:

f(x)

Results

Volume

0.628319 cubic units

Volume (exact)

0.2000π

Surface Area

3.809730 sq units

Method

Disk

Formula used:

V = π ∫[a,b] [f(x)]² dx

Cross-Section Radius at Sample Points

x = 0.00
R=0.000
x = 0.20
R=0.040
x = 0.40
R=0.160
x = 0.60
R=0.360
x = 0.80
R=0.640
x = 1.00
R=1.000
1.Method: Disk method (single curve rotated around x-axis)
2.Function: f(x) = x²
3.Bounds: [0, 1]
4.Formula: V = π ∫[a,b] [f(x)]² dx
5.Each cross-sectional disk has radius R(x) = |f(x)| and area A(x) = π·R(x)²
6.Volume = 0.2000π ≈ 0.628319 cubic units
7.Lateral surface area ≈ 3.809730 square units

Method Comparison Guide

FeatureDiskWasherShell
AxisPerpendicularPerpendicularParallel
Curves121 or 2
Integrandπ[f(x)]²π(R²−r²)2πx·f(x)
Best forSimple solidsHollow solidsy-axis rotation

How to Use This Calculator

  1. Select your integration method — Disk for single curves, Washer for the region between two curves, or Shell for cylindrical shells
  2. Enter your function(s) using standard notation: x^2, sqrt(x), sin(x), exp(x)
  3. Set the lower and upper bounds of integration
  4. Choose the rotation axis (x-axis or y-axis)
  5. Click "Calculate Volume" to see the volume, surface area, formula, and step-by-step solution
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Solid of Revolution Calculator: Find Volume by Disk, Washer, or Shell Method

About the Author

Marko Šinko - Co-Founder & Lead Developer

Marko Šinko

Co-Founder & Lead Developer, AI Math Calculator

Lepoglava, Croatia
Advanced Algorithm Expert

Croatian developer with a Computer Science degree from University of Zagreb and expertise in advanced algorithms. Co-founder of award-winning projects, ensuring precise mathematical computations and reliable calculator tools.

📅 Published:Updated:
Solid of Revolution Calculator showing 3D rotational volume with disk, washer, and shell method options and step-by-step solution.

A solid of revolution calculator takes a 2D curve, spins it around an axis, and hands you the exact volume of the resulting 3D shape — no integration by hand required. If you've ever stared at a textbook integral of the form V = π∫[f(x)]²dx and wondered whether you set up the radius correctly, this tool eliminates the guesswork. Enter a function, pick your bounds, choose disk, washer, or shell, and the calculator returns the volume in both decimal and exact (multiples of π) form, plus a step-by-step breakdown you can follow along with.

Solid of Revolution Calculator: Three Methods and When Each One Wins

There's no single "best" method for computing rotational volumes. The right choice depends on the axis of rotation, whether you're dealing with one curve or two, and which variable makes the integral cleaner. Here's the decision framework:

MethodFormulaUse When
DiskV = π ∫ₐᵇ [f(x)]² dxSingle curve rotated around an axis it touches (no hole in the middle)
WasherV = π ∫ₐᵇ [R(x)² − r(x)²] dxRegion between two curves — produces a hollow solid (like a donut or pipe)
ShellV = 2π ∫ₐᵇ x · |f(x)| dxRotation around an axis parallel to the slicing direction — often simpler for y-axis rotation

Quick rule of thumb: if the axis of rotation is perpendicular to your slices, use disk or washer. If it's parallel, shells are usually cleaner. For a deeper dive into each individual approach, see the dedicated disk method calculator, washer method calculator, or shell method calculator.

Worked Example: Rotating f(x) = x² Around the X-Axis

Rotate f(x) = x² around the x-axis from x = 0 to x = 1. Since the curve touches the axis and there's no inner boundary, the disk method applies directly:

V = π ∫₀¹ (x²)² dx

  = π ∫₀¹ x⁴ dx

  = π · [x⁵/5]₀¹

  = π · (1/5 − 0)

  = π/5 ≈ 0.628319 cubic units

That's a solid shaped roughly like a bullet — wider at x = 1 where the radius equals 1, tapering to a point at the origin where x² = 0.

Washer Example: Region Between √x and x²

Now for something more interesting. Take the region enclosed by f(x) = √x (outer) and g(x) = x² (inner) on [0, 1], rotated around the x-axis. These curves intersect at x = 0 and x = 1, creating a lens-shaped region. Spinning it produces a hollow solid:

V = π ∫₀¹ [(√x)² − (x²)²] dx

  = π ∫₀¹ [x − x⁴] dx

  = π · [x²/2 − x⁵/5]₀¹

  = π · (1/2 − 1/5)

  = 3π/10 ≈ 0.942478 cubic units

Notice how the washer method naturally subtracts the inner volume from the outer. If you'd used the disk method on each curve separately, you'd compute V(√x) − V(x²) = π/2 − π/5 = 3π/10 — same answer, but the washer formula does it in one integral. For problems involving regions between curves, the area between curves calculator can help you identify the bounds first.

When Shells Beat Disks (and Vice Versa)

Rotate f(x) = x² from 0 to 2 around the y-axis. You could express x in terms of y (x = √y) and integrate with disks from y = 0 to y = 4 — but shells keep everything in terms of x:

V = 2π ∫₀² x · x² dx = 2π ∫₀² x³ dx

  = 2π · [x⁴/4]₀² = 2π · 4

  = 8π ≈ 25.1327 cubic units

With disks, the same problem becomes V = π∫₀⁴ (√y)² dy = π∫₀⁴ y dy = π·8 = 8π. Same result, but you had to invert the function and change the bounds. For functions that are hard to invert (like x³ + sin(x)), shells are often the only practical path. The volume of revolution calculator page compares both methods side-by-side for a given function.

Surface Area of Revolution — The Formula Most Students Forget

Volume gets all the attention, but surface area of revolution shows up on exams just as often. The lateral surface area when rotating f(x) around the x-axis from a to b is:

S = 2π ∫ₐᵇ |f(x)| · √(1 + [f'(x)]²) dx

That √(1 + [f'(x)]²) factor is the arc length element — it accounts for the fact that a steeper curve produces more surface per unit of x. For f(x) = x² on [0, 1], the surface area integral evaluates to approximately 3.8097 square units. Our calculator computes this automatically alongside the volume, saving you the derivative and the messy square root.

For arc length calculations specifically, you might also find the arc length calculator useful — the integrand √(1 + [f'(x)]²) is identical.

Five Mistakes That Cost Points on Exams

  1. Squaring the wrong thing. In the disk formula V = π∫[f(x)]²dx, you square the function value (the radius), not the entire integrand. Writing π∫f(x)dx and squaring afterward gives a completely different number.
  2. Forgetting which curve is outer vs. inner. For washers, R(x) is whichever function is farther from the axis. If f(x) = √x and g(x) = x² on [0,1], then √x ≥ x² throughout, so R = √x. Swapping them gives a negative integrand — impossible for volume.
  3. Using the wrong method for the axis. Rotating around the y-axis with disks means you must express x as a function of y. Many students forget to change the bounds accordingly (x-bounds ≠ y-bounds).
  4. Ignoring absolute values. If f(x) dips below the axis of rotation, the radius is |f(x)|, not f(x). Squaring hides the sign for volume, but surface area requires the explicit absolute value.
  5. Wrong bounds for washer problems. The limits of integration are where the curves intersect, not arbitrary endpoints. Always solve f(x) = g(x) first to find a and b.

Quick Reference: Common Solids of Revolution

FunctionBoundsAxisResulting ShapeVolume
f(x) = r[0, h]x-axisCylinderπr²h
f(x) = (r/h)x[0, h]x-axisConeπr²h/3
f(x) = √(r²−x²)[−r, r]x-axisSphere4πr³/3
f(x) = x²[0, 1]x-axisParaboloidπ/5
R + r·cos(θ)[0, 2π]y-axisTorus2π²Rr²

Every familiar 3D shape with rotational symmetry can be derived from a solid of revolution. Cylinders, cones, spheres, toruses — they're all generated by spinning the right curve around the right axis. This calculator lets you verify textbook results or explore shapes that don't have neat closed-form volumes.

Where Solids of Revolution Show Up Beyond the Classroom

Engineering lathes literally create solids of revolution — a metal rod spins while a cutting tool traces a profile curve. The volume of material removed is a rotational volume integral. Fluid dynamics uses the same math: the volume of a tapered pipe section is π∫[r(x)]²dx, and getting it wrong means incorrect flow rate calculations.

In architecture, domes and cupolas are solids of revolution. The Pantheon's interior dome approximates a hemisphere — rotating f(x) = √(r² − x²) around the vertical axis. Pottery and glassblowing follow the same principle: the potter's wheel produces solids of revolution by definition.

Medical imaging (CT and MRI) reconstructs 3D organ volumes from 2D cross-sections — essentially reversing the disk method. If each slice at position x has area A(x), the total volume is ∫A(x)dx. The conceptual foundation is identical to what this calculator computes, scaled to real anatomy instead of polynomial functions. For related numerical integration techniques, the Simpson's rule calculator shows how the underlying approximation works.

Frequently Asked Questions

Do I rotate a curve or a region to create a solid of revolution?

Rotating a curve produces a surface; rotating a filled plane region produces a solid with volume. For y = x^2 from 0 to 1, specify the region between the curve and the x-axis before calculating a volume. The boundary alone does not identify which space should be filled.

How can I tell whether the rotated solid has a central hole?

Sketch a slice perpendicular to the rotation axis. If the filled region reaches the axis, that slice produces a disk. If there is a gap, it produces a washer with a positive inner radius. Having two boundary curves does not by itself guarantee a hole; their distances from the axis decide.

What is the formula for volume of a solid of revolution?

Volume is the integral of cross-sectional area: disks use πR^2 and washers use π(R^2-r^2). The shell method uses 2π times radius times height. Radii are distances from the chosen axis, not automatically x or f(x); identify them from the filled region and check that the slices cover the solid once.

How do you find the surface area of a solid of revolution?

The lateral surface area formula is S = 2pi integral from a to b of |f(x)| * sqrt(1 + [f'(x)]^2) dx. The sqrt(1 + [f'(x)]^2) factor is the arc length element, accounting for the curve's steepness. For f(x) = x^2 on [0,1], the surface area is approximately 3.81 square units.

Can I rotate a curve around any line, not just the x-axis or y-axis?

Yes. For rotation around a horizontal line y = k, replace f(x) with |f(x) - k| in the disk/washer formula. For rotation around a vertical line x = k, adjust the shell radius to |x - k|. The calculator supports both standard axes; for custom lines, adjust the function accordingly.

What are common solids of revolution I already know?

A cylinder comes from rotating a horizontal line, a cone from a slanted line, a sphere from a semicircle sqrt(r^2 - x^2), a paraboloid from x^2, and a torus (donut) from rotating a circle offset from the axis. Every rotationally symmetric object can be modeled this way.

Why does my solid of revolution integral give a negative volume?

A negative result usually means the outer and inner radii are swapped in a washer integral. The outer radius R(x) must always be the curve farther from the rotation axis. Also check your bounds: the lower limit should be less than the upper limit. Volume is always non-negative.