Stokes' Theorem Calculator - Curl Surface Integral Solver

Stokes' Theorem Calculator

Match a boundary line integral to the curl surface integral

Vector Field F(x, y, z) = ⟨P, Q, R⟩

Use x, y, z with + − * / ^ and functions like sin, cos, exp, sqrt.

Oriented Surface S (its edge is the closed curve C)

Load an example field

How to Use This Calculator

  1. Type the three components of your field into the P, Q, and R boxes (use x, y, z).
  2. Pick an oriented surface — disk, rectangle, hemisphere, or paraboloid — that the boundary curve C wraps around.
  3. Set the radius a (or rectangle bounds). The boundary curve is built automatically with the matching orientation.
  4. Press Verify Stokes' Theorem. The tool computes the circulation ∮ F·dr and the curl flux ∬(∇×F)·n dS.
  5. Read the match badge — equal values confirm the theorem; the step list shows every quantity.

Stokes' Theorem

∮_C F · dr = ∬_S (∇ × F) · n dS

Left side: circulation of F around the closed boundary curve C.

Right side: flux of the curl ∇ × F through the oriented surface S.

Orientation rule: C runs counter-clockwise when viewed along the normal n (right-hand rule).

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Stokes' Theorem Calculator: Converting Line Integrals to Surface Integrals of Curl

About the Author

Marko Šinko - Co-Founder & Lead Developer

Marko Šinko

Co-Founder & Lead Developer, AI Math Calculator

Lepoglava, Croatia
Advanced Algorithm Expert

Croatian developer with a Computer Science degree from University of Zagreb and expertise in advanced algorithms. Co-founder of award-winning projects, ensuring precise mathematical computations and reliable calculator tools.

📅 Published:
Stokes' theorem calculator showing a surface bounded by a closed loop with curl rotation arrows over an emerald field diagram.

A Stokes' theorem calculator turns a messy line integral around a closed loop into a surface integral of the curl — and this one does both halves so you can watch them land on the same number. Type a vector field, pick a surface, and it computes the circulation ∮C F·dr and the curl flux ∬S (∇×F)·n dS, then tells you whether they agree. That equality is the whole point of Stokes' theorem, and seeing it confirmed numerically beats reading the formula a tenth time.

What follows is the math behind the tool: what each side of the equation means, why orientation decides the sign, three worked surfaces that all share one boundary, and the traps that make a hand calculation disagree with the calculator.

What a Stokes' Theorem Calculator actually equates

Stokes' theorem states ∮C F·dr = ∬S (∇×F)·n dS. The left side adds up how hard the field F pushes along a closed curve C as you travel once around it — its circulation. The right side adds up how much the curl of F pokes through any surface S whose edge is that same curve C. The claim is bold: the boundary integral does not care which surface you stretch across C. A flat disk, a tall dome, a stretched paraboloid — same edge, same answer.

That surface-independence is exactly what the calculator lets you test. Keep the field ⟨−y, x, 0⟩ fixed, run it against the disk, then the hemisphere, then the paraboloid of radius 1. The boundary is the unit circle in every case, so all three return a circulation of 2π ≈ 6.2832 — and all three curl-flux integrals match it. The curl here is the constant vector (0, 0, 2); you can confirm that breakdown with a dedicated curl calculator before you trust the flux number.

Orientation is not a footnote — it sets the sign

More students lose marks to orientation than to the calculus. The rule: curl your right hand's fingers in the direction you walk around C, and your thumb has to point the same way as the surface normal n. Reverse the walk and every term flips sign — a perfectly correct integral comes out negative. The calculator removes that guesswork by building each boundary curve counter-clockwise as seen from the positive side of the normal, so the two sides are always set up to agree. If you compute by hand and get the right magnitude but the wrong sign, orientation is almost always the culprit.

One concrete consequence: an upward-pointing normal on a disk in the z = 0 plane forces the boundary circle to run counter-clockwise when you look down the z-axis. Flip to a downward normal and the circle must run clockwise to keep Stokes' theorem honest.

A worked example you can redo by hand

Take F = ⟨−y, x, 0⟩ over the unit disk in the z = 0 plane, and start with the right side. The curl is ∇×F = (∂(0)/∂y − ∂x/∂z, ∂(−y)/∂z − ∂(0)/∂x, ∂x/∂x − ∂(−y)/∂y) = (0, 0, 2). The normal is n = (0, 0, 1), so (∇×F)·n = 2. Integrating the constant 2 over a disk of area π gives 2π.

Now the left side. Parametrize the boundary as r(t) = (cos t, sin t, 0) for t from 0 to 2π. Then F·r'(t) = ⟨−sin t, cos t, 0⟩ · ⟨−sin t, cos t, 0⟩ = sin²t + cos²t = 1, and ∫₀²π 1 dt = 2π. Both sides equal 2π — yet the surface side never integrated the field along the curve, which is precisely why Stokes' theorem saves work. When a field has a simple curl but a nasty boundary, convert to the surface side; when the surface is awful but the boundary is a tidy circle, convert to the line side. This trade is the same logic behind a line integral calculator and a surface integral calculator, just bridged by curl.

Three surfaces, one boundary, identical answers

Here is the table the calculator reproduces for F = ⟨−y, x, 0⟩ with boundary radius 1. Every surface shares the unit-circle edge, so every circulation lands on 2π:

SurfaceNormal directionCurl flux ∬(∇×F)·n dS
Flat disk, z = 0Upward (0,0,1)2π ≈ 6.2832
Upper hemisphereOutward2π ≈ 6.2832
Paraboloid z = 1 − (x²+y²)Upward2π ≈ 6.2832

The hemisphere and paraboloid bulge far out of the plane, yet the answer never moves. That is surface-independence made visible — and it is the property that makes Stokes' theorem so useful in physics, where you get to swap an awkward surface for a convenient one with the same rim.

What the circulation number is telling you

The circulation ∮C F·dr measures net swirl around the loop. For the rotation field ⟨−y, x, 0⟩ it came out to exactly twice the enclosed area — no accident, since the curl was the constant 2 and the flux of a constant equals that constant times area. In fluid dynamics this is vorticity bookkeeping: the curl flux through a cross-section equals the circulation around its rim, which is how engineers tie a spinning core to the flow around it. In electromagnetism the same identity is Ampère's law in integral form — the line integral of the magnetic field around a loop equals the current threading any surface bounded by it. When circulation is zero on every loop, the field may be conservative, the same condition a divergence and curl check flags when it reports ∇×F = 0.

When the two sides refuse to match

Stokes' theorem has fine print, and the calculator's amber "does not match" badge usually points straight at it. The field and its first derivatives must be continuous on and around the surface. The classic failure is the vortex F = ⟨−y/(x²+y²), x/(x²+y²), 0⟩, whose curl is zero everywhere except the origin, where it blows up. Stretch a disk over the unit circle and the singularity sits right in the middle — the surface integral is undefined, even though the line integral happily returns 2π. The fix is to exclude the singular point or choose a surface that avoids it. A mismatch is rarely the theorem breaking; it is almost always a hole in the surface where the field is not smooth, a discontinuous component, or a boundary oriented backwards.

How it relates to Green's and the divergence theorem

Stokes' theorem is the 3D parent of Green's theorem. Flatten the surface into the z = 0 plane and the curl flux collapses to ∬(∂Q/∂x − ∂P/∂y) dA — Green's theorem exactly. Push instead to closed surfaces and you reach the divergence theorem, which trades surface flux for a volume integral of ∇·F. All three belong to the generalized Stokes' theorem family: integrate a derivative over a region, or integrate the original quantity over its boundary, and you get the same number. Knowing which member to reach for — circulation versus outward flux versus enclosed area — is half of vector calculus, and a quick pass through a flux calculator sharpens the difference between flux through a surface and circulation around its edge. For the formal statement and history, the Stokes' theorem reference is a solid next stop.

Frequently Asked Questions

How do you use Stokes' theorem to convert a line integral to a surface integral?

Replace the closed-curve circulation ∮_C F·dr with the curl flux ∬_S (∇×F)·n dS over any surface S whose edge is C. First compute the curl ∇×F = ⟨∂R/∂y − ∂Q/∂z, ∂P/∂z − ∂R/∂x, ∂Q/∂x − ∂P/∂y⟩, then integrate its dot product with the oriented normal over the surface. Pick the simplest surface bounded by C — a flat disk usually beats a curved one.

What does Stokes' theorem state?

Stokes' theorem states that ∮_C F·dr = ∬_S (∇×F)·n dS: the circulation of a vector field around a closed curve C equals the flux of its curl through any oriented surface S bounded by C. The result is independent of which surface you choose, as long as the boundary and orientation match.

Why do different surfaces with the same boundary give the same answer?

Because the curl field ∇×F is divergence-free (∇·(∇×F) = 0), its flux through any two surfaces sharing the same boundary is identical. For F = ⟨−y, x, 0⟩ on the unit circle, a flat disk, a hemisphere, and a paraboloid all return a circulation of 2π ≈ 6.2832. This surface-independence lets you swap an awkward surface for a convenient one.

What is the difference between Stokes' theorem and Green's theorem?

Green's theorem is the 2D special case of Stokes' theorem. When the surface lies flat in the z = 0 plane, the curl flux reduces to ∬(∂Q/∂x − ∂P/∂y) dA, which is exactly Green's theorem. Stokes' theorem generalizes this to curved surfaces in three dimensions.

How do I orient the boundary curve for Stokes' theorem?

Use the right-hand rule: point your right thumb along the surface normal n, and your curled fingers show the positive direction to traverse the boundary C. For an upward normal on a disk in the z = 0 plane, the boundary runs counter-clockwise viewed from above. Reverse the orientation and the integral flips sign.

Why does my Stokes' theorem calculation give different values on each side?

Check boundary orientation, parametrization, and whether the vector field is continuously differentiable on a neighborhood of the entire spanning surface. For F = (-y/(x^2+y^2), x/(x^2+y^2), 0), curl is zero away from the z-axis, yet circulation around a unit circle centered on that axis is 2π. Stokes’ theorem does not apply to the flat disk because it contains the singularity.

What is circulation in Stokes' theorem?

Circulation is the line integral ∮_C F·dr, the net amount the field pushes along the closed curve as you travel once around it. For the rotation field ⟨−y, x, 0⟩ the circulation equals twice the enclosed area. In physics it measures vorticity in fluid flow and, via Ampère's law, the current threading a loop in electromagnetism.